Reasoning Quiz for IBPS PO Mains: 17th November 2018 IN Hindi

To solve such kind of questions first we have to try to make family tree with the help of given conditions,

T and his brother are immediate neighbors of each other, it means T is male. Two persons sit between B’s father and Q. Q is daughter-in-law of A. B sits 2nd to the right of his sister-in-law, it means B is male from this case two possibilities will be there, either B has a married brother or B’s wife has a sister. Husband of C has only 2 grandchildren, it means C is a grandmother. Father-in-law of A has only 2 sons and one daughter, it means A is either daughter-in–law or son-in-law. T and R are children of F’s wife, hence F is father of T and R. Q and U are sisters. F is son of C, now it is clear that T and R are grandchildren of C. R is brother-in-law of Q, it means R is male and Q is wife of T. There is only one possibility that A will be wife of F and daughter-in-law of A’s parents. P is father of B who is uncle of T, from this statement it is clear that B is brother of F and P is husband of C. D will be the sister of both B and F and the possibility of B’s wife has a sister will be cancelled out because it is fixed that B has a married brother who is F.

Two persons sit between B’s father (P) and Q hence 2 possibilities will be there 1st is P will sit 3rd right of Q and 2nd is Q will sit 3rd right of P in row-1. But from the condition, Q is daughter-in-law of A and faces her father-in-law (F) who sits 2nd from the right end of the row because F sits on row-2 so he will face north he is 2nd from the right end of the row-2 and Q will be 2nd from the left end of the row 1, hence 2nd possibility will be cancelled out. T and his brother (R) are immediate neighbors of each other, from this condition Either T or R can sit immediate left of P and U’s position will be fixed. B sits 2nd to the right of his sister-in-law (A) and B does not sit at extreme end, so there is only one possibility that A will sit at extreme left end of row-2.

Aunt of R (D) doesn’t face T’s sister-in-law (U) and T, from this condition Case-2 will be eliminated because there is no position is left for D. Case-1 will be continued with this condition D’s position will be fixed that D will face R and C will sit at extreme right end of the row-2, finally we will get answer.

 

To solve such kind of questions first we have to try to make family tree with the help of given conditions,

T and his brother are immediate neighbors of each other, it means T is male. Two persons sit between B’s father and Q. Q is daughter-in-law of A. B sits 2nd to the right of his sister-in-law, it means B is male from this case two possibilities will be there, either B has a married brother or B’s wife has a sister. Husband of C has only 2 grandchildren, it means C is a grandmother. Father-in-law of A has only 2 sons and one daughter, it means A is either daughter-in–law or son-in-law. T and R are children of F’s wife, hence F is father of T and R. Q and U are sisters. F is son of C, now it is clear that T and R are grandchildren of C. R is brother-in-law of Q, it means R is male and Q is wife of T. There is only one possibility that A will be wife of F and daughter-in-law of A’s parents. P is father of B who is uncle of T, from this statement it is clear that B is brother of F and P is husband of C. D will be the sister of both B and F and the possibility of B’s wife has a sister will be cancelled out because it is fixed that B has a married brother who is F.

Two persons sit between B’s father (P) and Q hence 2 possibilities will be there 1st is P will sit 3rd right of Q and 2nd is Q will sit 3rd right of P in row-1. But from the condition, Q is daughter-in-law of A and faces her father-in-law (F) who sits 2nd from the right end of the row because F sits on row-2 so he will face north he is 2nd from the right end of the row-2 and Q will be 2nd from the left end of the row 1, hence 2nd possibility will be cancelled out. T and his brother (R) are immediate neighbors of each other, from this condition Either T or R can sit immediate left of P and U’s position will be fixed. B sits 2nd to the right of his sister-in-law (A) and B does not sit at extreme end, so there is only one possibility that A will sit at extreme left end of row-2.

Aunt of R (D) doesn’t face T’s sister-in-law (U) and T, from this condition Case-2 will be eliminated because there is no position is left for D. Case-1 will be continued with this condition D’s position will be fixed that D will face R and C will sit at extreme right end of the row-2, finally we will get answer.

To solve such kind of questions first we have to try to make family tree with the help of given conditions,

T and his brother are immediate neighbors of each other, it means T is male. Two persons sit between B’s father and Q. Q is daughter-in-law of A. B sits 2nd to the right of his sister-in-law, it means B is male from this case two possibilities will be there, either B has a married brother or B’s wife has a sister. Husband of C has only 2 grandchildren, it means C is a grandmother. Father-in-law of A has only 2 sons and one daughter, it means A is either daughter-in–law or son-in-law. T and R are children of F’s wife, hence F is father of T and R. Q and U are sisters. F is son of C, now it is clear that T and R are grandchildren of C. R is brother-in-law of Q, it means R is male and Q is wife of T. There is only one possibility that A will be wife of F and daughter-in-law of A’s parents. P is father of B who is uncle of T, from this statement it is clear that B is brother of F and P is husband of C. D will be the sister of both B and F and the possibility of B’s wife has a sister will be cancelled out because it is fixed that B has a married brother who is F.

Two persons sit between B’s father (P) and Q hence 2 possibilities will be there 1st is P will sit 3rd right of Q and 2nd is Q will sit 3rd right of P in row-1. But from the condition, Q is daughter-in-law of A and faces her father-in-law (F) who sits 2nd from the right end of the row because F sits on row-2 so he will face north he is 2nd from the right end of the row-2 and Q will be 2nd from the left end of the row 1, hence 2nd possibility will be cancelled out. T and his brother (R) are immediate neighbors of each other, from this condition Either T or R can sit immediate left of P and U’s position will be fixed. B sits 2nd to the right of his sister-in-law (A) and B does not sit at extreme end, so there is only one possibility that A will sit at extreme left end of row-2.

Aunt of R (D) doesn’t face T’s sister-in-law (U) and T, from this condition Case-2 will be eliminated because there is no position is left for D. Case-1 will be continued with this condition D’s position will be fixed that D will face R and C will sit at extreme right end of the row-2, finally we will get answer.

To solve such kind of questions first we have to try to make family tree with the help of given conditions,

T and his brother are immediate neighbors of each other, it means T is male. Two persons sit between B’s father and Q. Q is daughter-in-law of A. B sits 2nd to the right of his sister-in-law, it means B is male from this case two possibilities will be there, either B has a married brother or B’s wife has a sister. Husband of C has only 2 grandchildren, it means C is a grandmother. Father-in-law of A has only 2 sons and one daughter, it means A is either daughter-in–law or son-in-law. T and R are children of F’s wife, hence F is father of T and R. Q and U are sisters. F is son of C, now it is clear that T and R are grandchildren of C. R is brother-in-law of Q, it means R is male and Q is wife of T. There is only one possibility that A will be wife of F and daughter-in-law of A’s parents. P is father of B who is uncle of T, from this statement it is clear that B is brother of F and P is husband of C. D will be the sister of both B and F and the possibility of B’s wife has a sister will be cancelled out because it is fixed that B has a married brother who is F.

Two persons sit between B’s father (P) and Q hence 2 possibilities will be there 1st is P will sit 3rd right of Q and 2nd is Q will sit 3rd right of P in row-1. But from the condition, Q is daughter-in-law of A and faces her father-in-law (F) who sits 2nd from the right end of the row because F sits on row-2 so he will face north he is 2nd from the right end of the row-2 and Q will be 2nd from the left end of the row 1, hence 2nd possibility will be cancelled out. T and his brother (R) are immediate neighbors of each other, from this condition Either T or R can sit immediate left of P and U’s position will be fixed. B sits 2nd to the right of his sister-in-law (A) and B does not sit at extreme end, so there is only one possibility that A will sit at extreme left end of row-2.

Aunt of R (D) doesn’t face T’s sister-in-law (U) and T, from this condition Case-2 will be eliminated because there is no position is left for D. Case-1 will be continued with this condition D’s position will be fixed that D will face R and C will sit at extreme right end of the row-2, finally we will get answer.

To solve such kind of questions first we have to try to make family tree with the help of given conditions,

T and his brother are immediate neighbors of each other, it means T is male. Two persons sit between B’s father and Q. Q is daughter-in-law of A. B sits 2nd to the right of his sister-in-law, it means B is male from this case two possibilities will be there, either B has a married brother or B’s wife has a sister. Husband of C has only 2 grandchildren, it means C is a grandmother. Father-in-law of A has only 2 sons and one daughter, it means A is either daughter-in–law or son-in-law. T and R are children of F’s wife, hence F is father of T and R. Q and U are sisters. F is son of C, now it is clear that T and R are grandchildren of C. R is brother-in-law of Q, it means R is male and Q is wife of T. There is only one possibility that A will be wife of F and daughter-in-law of A’s parents. P is father of B who is uncle of T, from this statement it is clear that B is brother of F and P is husband of C. D will be the sister of both B and F and the possibility of B’s wife has a sister will be cancelled out because it is fixed that B has a married brother who is F.

Two persons sit between B’s father (P) and Q hence 2 possibilities will be there 1st is P will sit 3rd right of Q and 2nd is Q will sit 3rd right of P in row-1. But from the condition, Q is daughter-in-law of A and faces her father-in-law (F) who sits 2nd from the right end of the row because F sits on row-2 so he will face north he is 2nd from the right end of the row-2 and Q will be 2nd from the left end of the row 1, hence 2nd possibility will be cancelled out. T and his brother (R) are immediate neighbors of each other, from this condition Either T or R can sit immediate left of P and U’s position will be fixed. B sits 2nd to the right of his sister-in-law (A) and B does not sit at extreme end, so there is only one possibility that A will sit at extreme left end of row-2.

Aunt of R (D) doesn’t face T’s sister-in-law (U) and T, from this condition Case-2 will be eliminated because there is no position is left for D. Case-1 will be continued with this condition D’s position will be fixed that D will face R and C will sit at extreme right end of the row-2, finally we will get answer.

Number and letter both are arrange from left hand side together.

Pick a number in ascending order and word in descending order.

Number take as it is and if words first letter is vowel than add ‘z’ before word and if word started with consonant that add ‘a’. And so on.

Input: troy 25 beyond intense harm 16 upper 33 admit 23 10 20 shoot 11 out 8.

Step I: 8 zupper troy 25 beyond intense harm 16 33 admit 23 10 20 shoot 11 out

Step II: 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 shoot 11 out

Step III: 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 out

Step IV: 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 33 admit 23 20

Step V: 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond harm 33 admit 23

Step VI: 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond 33 admit

Step VII: 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 33 admit

Step VIII: 33 zadmit 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper

Step VIII is the last step of the above arrangement.

Number and letter both are arrange from left hand side together.

Pick a number in ascending order and word in descending order.

Number take as it is and if words first letter is vowel than add ‘z’ before word and if word started with consonant that add ‘a’. And so on.

Input: troy 25 beyond intense harm 16 upper 33 admit 23 10 20 shoot 11 out 8.

Step I: 8 zupper troy 25 beyond intense harm 16 33 admit 23 10 20 shoot 11 out

Step II: 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 shoot 11 out

Step III: 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 out

Step IV: 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 33 admit 23 20

Step V: 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond harm 33 admit 23

Step VI: 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond 33 admit

Step VII: 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 33 admit

Step VIII: 33 zadmit 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper

Step VIII is the last step of the above arrangement.

Number and letter both are arrange from left hand side together.

Pick a number in ascending order and word in descending order.

Number take as it is and if words first letter is vowel than add ‘z’ before word and if word started with consonant that add ‘a’. And so on.

Input: troy 25 beyond intense harm 16 upper 33 admit 23 10 20 shoot 11 out 8.

Step I: 8 zupper troy 25 beyond intense harm 16 33 admit 23 10 20 shoot 11 out

Step II: 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 shoot 11 out

Step III: 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 out

Step IV: 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 33 admit 23 20

Step V: 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond harm 33 admit 23

Step VI: 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond 33 admit

Step VII: 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 33 admit

Step VIII: 33 zadmit 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper

Step VIII is the last step of the above arrangement.

Number and letter both are arrange from left hand side together.

Pick a number in ascending order and word in descending order.

Number take as it is and if words first letter is vowel than add ‘z’ before word and if word started with consonant that add ‘a’. And so on.

Input: troy 25 beyond intense harm 16 upper 33 admit 23 10 20 shoot 11 out 8.

Step I: 8 zupper troy 25 beyond intense harm 16 33 admit 23 10 20 shoot 11 out

Step II: 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 shoot 11 out

Step III: 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 out

Step IV: 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 33 admit 23 20

Step V: 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond harm 33 admit 23

Step VI: 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond 33 admit

Step VII: 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 33 admit

Step VIII: 33 zadmit 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper

Step VIII is the last step of the above arrangement.

Number and letter both are arrange from left hand side together.

Pick a number in ascending order and word in descending order.

Number take as it is and if words first letter is vowel than add ‘z’ before word and if word started with consonant that add ‘a’. And so on.

Input: troy 25 beyond intense harm 16 upper 33 admit 23 10 20 shoot 11 out 8.

Step I: 8 zupper troy 25 beyond intense harm 16 33 admit 23 10 20 shoot 11 out

Step II: 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 shoot 11 out

Step III: 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 16 33 admit 23 20 out

Step IV: 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond intense harm 33 admit 23 20

Step V: 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond harm 33 admit 23

Step VI: 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 25 beyond 33 admit

Step VII: 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper 33 admit

Step VIII: 33 zadmit 25 abeyond 23 aharm 20 zintense 16 zout 11 ashoot 10 atroy 8 zupper

Step VIII is the last step of the above arrangement.

Letters written against numbers 3, 6, 7, 12 are—R, E, V, Y.

Word formed—VERY. So letter is E.

“M”

Total no. of student=56

Boys: Girls=5:3, So Boys=35 and Girls=21

We don’t know the exact number of girls sitting ahead or behind Shalini, so can’t be determine.