S1. Ans.(d)
Sol.
S2. Ans.(e)
Sol.
S3. Ans.(d)
Sol.
S4. Ans.(c)
Sol.
S5. Ans.(c)
Sol.
S6. Ans.(c)
Sol. Conclusions:
I. N * R ( Not True )
II. N $ R ( Not True )
III. S $ M ( True )
S7. Ans.(d)
Sol. Conclusions:
I. J % T ( Not True )
II. K % N ( True )
III. N @ J ( True )
S8. Ans.(c)
Sol. Conclusions:
I. B $ F ( Not True )
II. D # F ( Not True )
III. D $ F ( Not True )
S9. Ans.(a)
Sol. Conclusions:
I. M # L ( True )
II. R $ U ( True )
III. R @ K ( True )
S10. Ans.(d)
Sol. Conclusions:
I. R # A ( Not True )
II. V @ R ( Not True )
III. R $ M ( Not True )
S11. Ans.(a)
Sol. First letter of the code is obtained from reversing (A-Z, B-Y…) the alphabet which has the same rank as the total number of alphabets in the word.
For example – Trees->Total number of letters=5=Rank of E, reverse of E is V. So, the first letter of the code=V
The number in the code represents the total number of letters in the word divided by 2.
For example – Trees – total number of letters=5/2= 2.5
The last letter of the code is obtained from reversing (A-Z, B-Y…) the last letter of the word.
Trees→ Reverse of S is H. So, the code for trees is V2.5H
S12. Ans.(e)
Sol. First letter of the code is obtained from reversing (A-Z, B-Y…) the alphabet which has the same rank as the total number of alphabets in the word.
For example – Trees->Total number of letters=5=Rank of E, reverse of E is V. So, the first letter of the code=V
The number in the code represents the total number of letters in the word divided by 2.
For example – Trees – total number of letters=5/2= 2.5
The last letter of the code is obtained from reversing (A-Z, B-Y…) the last letter of the word.
Trees→ Reverse of S is H. So, the code for trees is V2.5H
S13. Ans.(c)
Sol. First letter of the code is obtained from reversing (A-Z, B-Y…) the alphabet which has the same rank as the total number of alphabets in the word.
For example – Trees->Total number of letters=5=Rank of E, reverse of E is V. So, the first letter of the code=V
The number in the code represents the total number of letters in the word divided by 2.
For example – Trees – total number of letters=5/2= 2.5
The last letter of the code is obtained from reversing (A-Z, B-Y…) the last letter of the word.
Trees→ Reverse of S is H. So, the code for trees is V2.5H
S14. Ans.(e)
Sol. First letter of the code is obtained from reversing (A-Z, B-Y…) the alphabet which has the same rank as the total number of alphabets in the word.
For example – Trees->Total number of letters=5=Rank of E, reverse of E is V. So, the first letter of the code=V
The number in the code represents the total number of letters in the word divided by 2.
For example – Trees – total number of letters=5/2= 2.5
The last letter of the code is obtained from reversing (A-Z, B-Y…) the last letter of the word.
Trees→ Reverse of S is H. So, the code for trees is V2.5H
S15. Ans.(d)
Sol. First letter of the code is obtained from reversing (A-Z, B-Y…) the alphabet which has the same rank as the total number of alphabets in the word.
For example – Trees->Total number of letters=5=Rank of E, reverse of E is V. So, the first letter of the code=V
The number in the code represents the total number of letters in the word divided by 2.
For example – Trees – total number of letters=5/2= 2.5
The last letter of the code is obtained from reversing (A-Z, B-Y…) the last letter of the word.
Trees→ Reverse of S is H. So, the code for trees is V2.5H
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